若ch为char型,能正确判断出“ch为数字”的表达式是()。
A.(ch>='0')||(ch<='9')
B.'0'<=ch<='9'
C.('0'<=ch)and('9'>=ch)
D.(ch>='0')&&(ch<='9')
A.(ch>='0')||(ch<='9')
B.'0'<=ch<='9'
C.('0'<=ch)and('9'>=ch)
D.(ch>='0')&&(ch<='9')
A.'A'<=ch<='Z'
B.(ch>='A')&(ch<='Z')
C.(ch>='A')&&(ch<='Z')
D.('A'<=ch)AND('Z'>=ch)
class A
{
int a;
A(int b)
{a=b;}
void show()
{System.out.println(“a=”+a);}
}
public class Class1
{
public static void main (String args[])
{
A bj=new A(12345);
boolean b=false;
char ch=97;
obj.show();
System.out.println(“b=”+b+”/tch=”+ch);
}
}
A.只有②④⑤
B.只有①③④
C.只有①②③④
D.1,2-二溴环丙烷
E.①②③④⑤
A.'a'<=c<='z'
B.(c>=a)&&(c<=z)
C.('a'>=c)('z'<=c)
D.(c>='a')&&(c<='z')
A.'a'<=c1<='z'
B.(c1>='a')&&(c1<='z')
C.(c1>=a)&&(c1<=z)
D.(‘a'<=c1)||('z'>=c1)
printf("*");
A.97<=cl<=122
B.(97>=cl)||(122<=cl)
C.(cl>=97)&&(cl<=122)
D.(cl>='97')&&(cl<='122')
A.ch:=’abcd’;
B.ch:=chr(ord(succ(‘c’)+1))
C.ch:=ord(‘b’)+ord(‘a’);
D.ch:=pred(succ(succ(‘f’)));